The study of energy transformations. It deals with macroscopic systems (bulk properties) in equilibrium, independent of the rate of reaction.
System:
The specific part of the universe under observation.
Surroundings:
The rest of the universe outside the system. Universe = System + Surroundings.
Boundary:
The real or imaginary, rigid or flexible wall separating the system from the surroundings,.
Open System:
Can exchange both matter and energy with surroundings (e.g., reactants in an open beaker).
Closed System:
Can exchange only energy, not matter, with surroundings (e.g., reactants in a sealed copper or steel vessel).
Isolated System:
Can exchange neither energy nor matter (e.g., reactants in a perfectly insulated thermos flask).
State of the System:
Described by measurable macroscopic properties (state variables) like Pressure (ppp), Volume (VVV), Temperature (TTT), and amount (nnn),.
State Functions:
Variables whose values depend only on the initial and final states of the system, not on the path taken. Examples: p,V,T,U,H,S,Gp, V, T, U, H, S, Gp,V,T,U,H,S,G,,,,.
Path Functions:
Variables whose values depend on the route/path taken. Examples: Heat (qqq) and Work (www),.JEE TIPIf you see qqq or www alone, they are path functions. But specific combinations like qpq_pqp (which equals ΔH\Delta HΔH) or qvq_vqv (which equals ΔU\Delta UΔU) are state functions,!
Extensive Properties:
Depend on the quantity or size of matter present. Examples: Mass, volume (VVV), internal energy (UUU), enthalpy (HHH), heat capacity (CCC), entropy (SSS), Gibbs energy (GGG),,.
Intensive Properties:
Independent of the quantity or size of matter. Examples: Temperature (TTT), density, pressure (ppp), specific heat capacity (ccc), molar heat capacity (CmC_mCm), molar volume (VmV_mVm),.JEE TIPThe ratio of two extensive properties is always an intensive property (e.g., Mass/Volume=DensityMass / Volume = DensityMass/Volume=Density; HeatCapacity/Moles=MolarHeatCapacityHeat Capacity / Moles = Molar Heat CapacityHeatCapacity/Moles=MolarHeatCapacity).
Important Rules, Laws & Principles
First Law of Thermodynamics (FLOT) / Law of Conservation of Energy: The energy of an isolated system is constant. Energy can neither be created nor destroyed. Mathematical form: ΔU=q+w,.
Hess's Law of Constant Heat Summation: If a reaction takes place in several steps, its standard reaction enthalpy is the sum of the standard enthalpies of the intermediate reactions at the same temperature. Enthalpy change is independent of the path.
Second Law of Thermodynamics: In an isolated system, there is always a tendency for the system's energy to become more disordered. For a spontaneous process, the entropy of the universe always increases (ΔStotal=ΔSsys+ΔSsurr>0),.
Third Law of Thermodynamics: The entropy of any perfectly pure crystalline substance approaches zero as the temperature approaches absolute zero (0 K).
Thermochemical Equation Conventions:
Coefficients strictly represent moles, not molecules,.
The physical state must be specified because enthalpy changes with phase.
If you multiply/divide the coefficients of an equation, you must multiply/divide the ΔrH⊖ by the same factor.
Reversing the reaction reverses the sign of ΔrH⊖.
Work, Heat, and Internal Energy
Internal Energy (U): Sum of all types of energy (chemical, electrical, mechanical) associated with a system. Absolute U cannot be calculated; only ΔU is measured.
Heat (q): Energy transfer due to a temperature difference.
Work (w): Mechanical transfer of energy. Pressure-volume work is given by w=−pexΔV.
IUPAC Sign Conventions:JEE TIPAlways use these strictly in Chemistry to avoid sign errors in numericals,!
q>0 (+): Heat absorbed by the system (Endothermic).
q<0 (-): Heat released from the system (Exothermic).
w>0 (+): Work done on the system (Compression),.
w<0 (-): Work done by the system (Expansion).
Reversible vs. Irreversible Processes:
Reversible: Process proceeds infinitely slowly by a series of equilibrium states such that system and surroundings are always in near equilibrium. pex≈pin±dp.
Irreversible: Process carried out rapidly or against a constant external pressure.
Free Expansion: Expansion of a gas into a vacuum (pex=0).JEE TIPWork done in free expansion is ALWAYS zero (w=0), regardless of whether the process is reversible or irreversible. For isothermal free expansion of an ideal gas: ΔU=0,q=0,w=0.
Enthalpy and Heat Capacity
Enthalpy (H): Defined as H=U+pV. It represents the total heat content of a system.
Heat Transfer Conditions:
Heat transferred at constant volume (qv) = ΔU.
Heat transferred at constant pressure (qp) = ΔH,.
Relation between ΔH and ΔU:
General: ΔH=ΔU+pΔV (at constant p).
For Ideal Gases: ΔH=ΔU+ΔngRT.
JEE TIPΔng ONLY includes gaseous species! Δng=(∑moles of gaseous products)−(∑moles of gaseous reactants). Treat solids and liquids as having negligible volume changes (ΔV≈0).
Heat Capacity (C): The heat required to raise the temperature of a system by 1∘C or 1 K,.
Specific Heat Capacity (c): per unit mass (q=mcΔT).
Molar Heat Capacity (Cm): per mole (q=nCmΔT),.
Cp and Cv: Molar heat capacity at constant pressure (Cp) and constant volume (Cv).
For an ideal gas: Cp−Cv=R.
Calorimetry & Measurement
Bomb Calorimeter: Used to measure heat of combustion. The steel vessel is sealed (constant volume, ΔV=0).JEE TIPBomb calorimetry measures ΔU (qv), NOT ΔH. You must use ΔH=ΔU+ΔngRT to find the enthalpy of reaction afterward,.
Constant Pressure Calorimeter: A simple calorimeter open to atmospheric pressure. Measures ΔH (qp).
Thermochemistry & Types of Enthalpy
Standard Enthalpy of Reaction (ΔrH⊖): Enthalpy change when all participating substances are in standard states (pure form at 1 bar pressure),.
Standard Enthalpy of Formation (ΔfH⊖): Enthalpy change when one mole of a compound is formed from its constituent elements in their most stable reference states,.
JEE TIPThe ΔfH⊖ of elements in their standard reference states (e.g., O2(g), C(graphite), S(rhombic), H2(g)) is exactly ZERO,.
Standard Enthalpy of Combustion (ΔcH⊖): Enthalpy change when one mole of a substance undergoes complete combustion in excess oxygen. Always highly exothermic (ΔcH⊖<0),.
Enthalpies of Phase Transformations:
Standard Enthalpy of Fusion (ΔfusH⊖): Enthalpy change when 1 mole of solid melts in standard state,. Always positive (endothermic).
Standard Enthalpy of Vaporization (ΔvapH⊖): Heat required to vaporize 1 mole of liquid at constant T and 1 bar. Magnitude depends on intermolecular forces (e.g., higher for water due to H-bonding compared to acetone).
Standard Enthalpy of Sublimation (ΔsubH⊖): Direct conversion of 1 mole of solid to vapor at constant T and 1 bar (e.g., solid CO2 or naphthalene),.
Enthalpy of Atomization (ΔaH⊖): Enthalpy change on breaking one mole of bonds completely to obtain individual atoms in the gas phase,.
Bond Enthalpy (ΔbondH⊖):
Diatomic molecules: Bond dissociation enthalpy equals enthalpy of atomization,.
Polyatomic molecules: Successive bond breaking requires different energies (e.g., the 4 C-H bonds in CH4),. Hence, we use Mean Bond Enthalpy.
Lattice Enthalpy (ΔlatticeH⊖): Enthalpy change when one mole of an ionic compound dissociates into its gaseous ions (Endothermic: ΔH>0). Calculated via the Born-Haber Cycle,,.
Enthalpy of Solution (ΔsolH⊖):ΔsolH⊖=ΔlatticeH⊖+ΔhydH⊖,. If lattice enthalpy is very high compared to hydration enthalpy, the salt is insoluble.
Enthalpy of Dilution: The heat withdrawn from the surroundings when additional solvent is added to a solution,. It depends on the original concentration of the solution and the amount of solvent added. Approaches a limiting value at infinite dilution.
Temperature Dependence of Ionization Energy and Electron Affinity (Kirchhoff's equation application): Ionization energy and electron affinity are technically defined at absolute zero (0 K). At any other temperature T, heat capacities (Cp) must be accounted for. For ionization (M(g)→M+(g)+e−), ΔrCp⊖=+5/2R. Thus, ΔionH⊖=E0(ionization energy)+5/2RT.
Spontaneity, Entropy, and Gibbs Energy
Entropy (S): State function measuring the degree of randomness or disorder,. (Sgas>Sliquid>Ssolid).
Entropy of Mixing (Diffusion): When a partition between two gases is removed, they spontaneously diffuse. The driving force is not an energy decrease (ΔH=0), but rather the system becoming less predictable and more chaotic (increase in entropy),.
Gibbs Free Energy (G):G=H−TS. An extensive state function. ΔG gives the net energy available to do useful work.
Criteria for Spontaneity (at constant T and P):
ΔG<0: Spontaneous.
ΔG>0: Non-spontaneous.
ΔG=0: Equilibrium.
Effect of Temperature on Spontaneity (ΔG=ΔH−TΔS):
ΔH<0,ΔS>0: Spontaneous at ALL temperatures (ΔG<0).
ΔH>0,ΔS<0: Non-spontaneous at ALL temperatures (ΔG>0).
ΔH>0,ΔS>0: Spontaneous at HIGH temperatures (entropy driven),.
ΔH<0,ΔS<0: Spontaneous at LOW temperatures (enthalpy driven).
Gibbs Energy and Equilibrium:JEE TIPAt equilibrium, ΔG=0, but standard Gibbs energy ΔG⊖ is NOT zero unless K=1. The relation is ΔG⊖=−RTlnK.
Relation between Cp and Cv:Cp−Cv=R (for ideal gas)
Enthalpy of Reaction (from formation enthalpies):ΔrH⊖=∑aiΔfH⊖(products)−∑biΔfH⊖(reactants),
Enthalpy of Reaction (from bond enthalpies):ΔrH⊖=∑Bond Enthalpies(Reactants)−∑Bond Enthalpies(Products),
Entropy Change:ΔS=Tqrev
Total Entropy Change:ΔStotal=ΔSsys+ΔSsurr
Gibbs Energy Change:ΔG=ΔH−TΔS,
Standard Gibbs Energy & Equilibrium:ΔrG⊖=−RTlnK=−2.303RTlogK
⚠️ EXCEPTIONS & ANOMALIES
Exception in the Third Law of Thermodynamics: The entropy of a perfectly pure crystalline solid approaches zero at absolute zero (0 K). Why is this an exception space? Theoretical arguments and practical evidence show that the entropy of solutions and supercooled liquids is NOT zero at 0 K. They are frozen in a disordered state.
Anomaly in Polyatomic Bond Enthalpies: In a polyatomic molecule like CH4, breaking the four C-H bonds successively requires different amounts of energy (e.g., 427, 439, 452, and 347 kJ/mol),,. Why? Each time a bond is broken, the remaining fragment changes its electronic and structural environment. Therefore, we use a Mean Bond Enthalpy for polyatomic molecules.
Exception to ΔH=ΔU: The difference between ΔH and ΔU is usually not significant for systems consisting solely of solids and liquids. Why? Because solids and liquids do not suffer any significant volume changes upon heating or reacting (ΔV≈0), making pΔV≈0.
Exception to Enthalpy Driving Spontaneity: While a decrease in enthalpy (exothermic processes) is a major contributory factor for spontaneity, endothermic reactions can also be strictly spontaneous,. Why? Processes like the dissolution of salts, melting of ice, or mixing of two gases occur spontaneously despite absorbing heat because the driving force is a massive increase in entropy (disorder) that overrides the enthalpy cost,.
Anomaly in Fluoride Solubility: Fluorides tend to be significantly less soluble in water than their corresponding chlorides. Why? Solubility depends on the balance between lattice enthalpy and hydration enthalpy,. Fluorides have exceptionally high lattice enthalpies that often cannot be overcome by their hydration enthalpies.
Anomaly in defining Ionization Energy and Electron Affinity terms: Earlier definitions used "Ionization energy" and "Electron affinity" purely as energy terms. Thermodynamic principles strictly differentiate them now as Enthalpy of Ionization and Electron Gain Enthalpy. Why? Because true Ionization Energy is measured at absolute zero (0 K). At room temperature (298 K), the thermal heat capacities of the gases (5/2RT) alter the total enthalpy,.
Previous Year JEE Topics
Isothermal Reversible vs Irreversible Work Calculation: Extremely frequent. Direct application of formula vs equating area under the curve,,,.
Calculation of ΔH from ΔU (ΔngRT relation): Usually embedded in bomb calorimeter word problems,.
Hess's Law and Enthalpy of Formation/Combustion: Combining 3-4 thermochemical equations to find the ΔH of a target equation,,.
Born-Haber Cycle: Calculating lattice enthalpy from sublimation, ionization, dissociation, and electron gain enthalpies,. Watch out for stoichiometry (e.g., taking half of the Cl2 dissociation energy),.
Spontaneity and Gibbs Free Energy: Determining the temperature range at which a reaction becomes spontaneous by setting ΔG=0 and solving for T=ΔH/ΔS,,.
Equilibrium Constant and ΔG⊖: Utilizing ΔrG⊖=−2.303RTlogK and applying antilogarithms to find K. Ensure units match (R = 8.314 J/K mol, and ΔG⊖ usually in kJ/mol must be converted to J/mol).
Top 10 JEE MCQ Traps
Misconception: Heat (q) and Work (w) are state functions just like internal energy. → Correct Understanding:q and w are path functions; their values depend on how the process is carried out,. However, specific boundary conditions turn them into state functions: qv (heat at constant volume) equals ΔU, and qp (heat at constant pressure) equals ΔH.
Misconception: Work done on the system by a gas expanding is positive. → Correct Understanding: Under IUPAC chemistry conventions, work done by the system (expansion, ΔV>0) loses energy, so w is negative. Work done on the system (compression, ΔV<0) stores energy, so w is positive (w=−pexΔV),. Physics conventions are reversed!
Misconception: Free expansion of a gas (ΔU=0,q=0) only applies if the process is reversible. → Correct Understanding: Work done during the free expansion of an ideal gas into a vacuum (pex=0) is ALWAYS zero, whether the process is reversible or irreversible.
Misconception: The change in number of moles (Δng) for ΔH=ΔU+ΔngRT includes all reactants and products. → Correct Understanding:Δng strictly includes only the gaseous species. Moles of solids and liquids must be completely ignored in this calculation.
Misconception: Bond enthalpy of reaction is calculated the same way as Enthalpy of Formation (Products - Reactants). → Correct Understanding: Bond enthalpy calculations are reversed! It is Σ Bond Enthalpies (Reactants) – Σ Bond Enthalpies (Products),. You put energy in to break reactant bonds, and energy is released out when product bonds form.
Misconception: Bomb calorimeters measure the Enthalpy of Combustion (ΔcH). → Correct Understanding: Bomb calorimeters are sealed steel vessels with constant volume (ΔV=0). Therefore, they measure heat at constant volume (qv), which is exactly equal to Internal Energy Change (ΔU), not ΔH. Questions will ask for Enthalpy of Combustion (ΔH) forcing you to calculate Δng and apply the conversion formula,.
Misconception: The enthalpy of formation for any element in any state is zero. → Correct Understanding: It is only zero for an element in its standard reference state (most stable state of aggregation at 1 bar and 25°C). For example, ΔfH⊖ of C(graphite) is zero, but C(diamond) is NOT zero. O2(g) is zero, but O3(g) is NOT zero.
Misconception: The standard Gibbs free energy (ΔG⊖) of a reaction is zero when the system is at equilibrium. → Correct Understanding: The total Gibbs free energy (ΔG) is zero at equilibrium, not ΔG⊖. The standard Gibbs free energy is a constant for a given reaction and temperature, defined by ΔG⊖=−RTlnK. It is only zero if the equilibrium constant K is exactly 1.
Misconception: A reaction is spontaneous anytime the entropy of the system increases (ΔSsys>0). → Correct Understanding: The Second Law dictates that the total entropy of the universe (ΔStotal=ΔSsys+ΔSsurr) must be greater than zero for spontaneity, not just the system. Alternatively, ΔGsys must be negative at constant T and P.
Misconception: Exothermic reactions (ΔH<0) are always spontaneous at all temperatures. → Correct Understanding: Spontaneity depends on both ΔH and ΔS,. If a reaction is exothermic (ΔH<0) but leads to more order (ΔS<0), it will only be spontaneous at low temperatures where the enthalpy term dominates the TΔS term. At high temperatures, it becomes non-spontaneous.
Notes fade fast. Rhovecs re-surfaces each concept on a forgetting schedule and picks what you practise next — so revision sticks.See how it works