Math · Trigonometry

Trigonometric Functions revision notes

A concise JEE revision summary of Trigonometric Functions.

FormulasRevision notes
Mathrevision notes

Key Concepts & Definitions

Introduction to Trigonometry The word ‘trigonometry’ is derived from the Greek words ‘trigon’ and ‘metron’, which literally means ‘measuring the sides of a triangle’. Originally developed for geometry, navigation, and surveying, it is now used extensively in fields like seismology, electrical circuits, and analyzing musical tones.

Angles and Rotation An angle is defined as a measure of rotation of a given ray about its initial point (vertex).

Initial and Terminal Sides:
The original position of the ray is the initial side, and its final position after rotation is the terminal side.
Sign Convention for Rotation:
If the direction of rotation is anticlockwise, the angle is positive; if it is clockwise, the angle is negative. → [JEE TIP] Always verify the direction of rotation in mechanics and phasor diagrams, as clockwise rotation introduces a negative phase shift.

Systems of Angle Measurement Angles are quantified by the amount of rotation from the initial to the terminal side.

  • Degree Measure: If a rotation from the initial to the terminal side is 1360th\frac{1}{360}^{th} of a full revolution, the angle has a measure of one degree (1°).
    • 1 degree (1°) = 60 minutes (60').
    • 1 minute (1') = 60 seconds (60").
  • Radian Measure: An angle subtended at the center of a unit circle by an arc of length 1 unit is defined as 1 radian. Radians and real numbers are considered one and the same mathematically, mapped directly by wrapping a real number line around the unit circle.

Trigonometric Functions via the Unit Circle Consider a unit circle (a2+b2=1a^2 + b^2 = 1) centered at the origin. For any point P(a,b)P(a, b) on the circle where the angle substituted from the positive x-axis is xx radians:

  • cosx=a\cos x = a
  • sinx=b\sin x = b From this, the fundamental identity naturally arises: sin2x+cos2x=1\sin^2 x + \cos^2 x = 1.

Historical Note The study of trigonometry as known today originated in India with mathematicians like Aryabhatta, Brahmagupta, and Bhaskara I and II. The concept of the "sine" of an angle represents the main contribution of Sanskrit astronomical works to mathematics. Thales is historically credited with determining the height of an Egyptian pyramid using shadows (similar triangles).

Measurement & Conversion Formulae

Arc Length Formula:

  • l=rθl = r\theta, where ll is arc length, rr is the radius, and θ\theta is the angle subtended at the center in radians. → [JEE TIP] A massive MCQ trap is plugging θ\theta in degrees into this formula. Always convert θ\theta to radians first.

Degree-Radian Conversion: One complete revolution subtends 2π2\pi radians, which equals 360°.

  • π radian=180\pi \text{ radian} = 180^\circ.
  • 1 radian=180π57161 \text{ radian} = \frac{180^\circ}{\pi} \approx 57^\circ 16'.
  • 1=π180 radian0.01746 radian1^\circ = \frac{\pi}{180} \text{ radian} \approx 0.01746 \text{ radian}.

Domain, Range & Sign of Trigonometric Functions

Domain and Range Because the coordinates (a,b)(a, b) on the unit circle are bounded between -1 and 1 (1a1-1 \le a \le 1 and 1b1-1 \le b \le 1), the sine and cosine functions are bounded.

  • y=sinxy = \sin x and y=cosxy = \cos x: Domain = all real numbers (R\mathbb{R}); Range = [1,1][-1, 1].
  • y=cosec xy = \text{cosec } x: Domain = {xR:xnπ,nZ}\{x \in \mathbb{R} : x \ne n\pi, n \in \mathbb{Z}\}; Range = (,1][1,)(-\infty, -1] \cup [1, \infty).
  • y=secxy = \sec x: Domain = {xR:x(2n+1)π2,nZ}\{x \in \mathbb{R} : x \ne (2n+1)\frac{\pi}{2}, n \in \mathbb{Z}\}; Range = (,1][1,)(-\infty, -1] \cup [1, \infty). → [JEE TIP] The equations secx=k\sec x = k or cosec x=k\text{cosec } x = k have no real solutions if 1<k<1-1 < k < 1.
  • y=tanxy = \tan x: Domain = {xR:x(2n+1)π2,nZ}\{x \in \mathbb{R} : x \ne (2n+1)\frac{\pi}{2}, n \in \mathbb{Z}\}; Range = R\mathbb{R}.
  • y=cotxy = \cot x: Domain = {xR:xnπ,nZ}\{x \in \mathbb{R} : x \ne n\pi, n \in \mathbb{Z}\}; Range = R\mathbb{R}.

ASTC Sign Convention The signs of functions depend on the quadrant in which the terminal side of the angle lies.

  • Quadrant I (0<x<π20 < x < \frac{\pi}{2}): All functions are positive.
  • Quadrant II (π2<x<π\frac{\pi}{2} < x < \pi): Only sinx\sin x and cosec x\text{cosec } x are positive.
  • Quadrant III (π<x<3π2\pi < x < \frac{3\pi}{2}): Only tanx\tan x and cotx\cot x are positive.
  • Quadrant IV (3π2<x<2π\frac{3\pi}{2} < x < 2\pi): Only cosx\cos x and secx\sec x are positive.

Periodicity & Quadrantal Angles Angles that are integral multiples of π2\frac{\pi}{2} are called quadrantal angles.

  • sinx=0\sin x = 0 implies x=nπx = n\pi (where nZn \in \mathbb{Z}).
  • cosx=0\cos x = 0 implies x=(2n+1)π2x = (2n+1)\frac{\pi}{2} (where nZn \in \mathbb{Z}).
  • Since one complete revolution brings the point back to its original position, sin(2nπ+x)=sinx\sin(2n\pi + x) = \sin x and cos(2nπ+x)=cosx\cos(2n\pi + x) = \cos x. → [JEE TIP] To find the value of large angles (e.g., sin(1710)\sin(1710^\circ)), continuously subtract 360360^\circ (2π2\pi) until the angle is within the principal range [0,360][0, 360^\circ].

Important Graphs & Diagrams

The values of trigonometric functions change continuously as the angle xx varies from 00 to 2π2\pi.

  • Sine Function: Increases from 010 \to 1 (Quad I), decreases 101 \to 0 (Quad II), decreases 010 \to -1 (Quad III), increases 10-1 \to 0 (Quad IV).
  • Cosine Function: Decreases 101 \to 0 (Quad I), decreases 010 \to -1 (Quad II), increases 10-1 \to 0 (Quad III), increases 010 \to 1 (Quad IV).
  • Tangent Function: Increases from 00 \to \infty in Quad I, increases from 0-\infty \to 0 in Quad II. It repeats after an interval of π\pi. The statement "tanx\tan x increases from 00 \to \infty" means it assumes arbitrarily large positive values as xx approaches π2\frac{\pi}{2}.
  • Secant & Cosecant: Their graphs feature asymptotes where cosx=0\cos x = 0 and sinx=0\sin x = 0, respectively. They never cross the horizontal band between y=1y = -1 and y=1y = 1.

Formulae, Equations & Units

Basic Fundamental Identities:

  • cos(x)=cosx\cos(-x) = \cos x (Even function).
  • sin(x)=sinx\sin(-x) = -\sin x (Odd function).
  • sin2x+cos2x=1\sin^2 x + \cos^2 x = 1.
  • 1+tan2x=sec2x1 + \tan^2 x = \sec^2 x.
  • 1+cot2x=cosec2x1 + \cot^2 x = \text{cosec}^2 x.

Sum and Difference of Angles:

  • cos(x+y)=cosxcosysinxsiny\cos(x + y) = \cos x \cos y - \sin x \sin y.
  • cos(xy)=cosxcosy+sinxsiny\cos(x - y) = \cos x \cos y + \sin x \sin y.
  • sin(x+y)=sinxcosy+cosxsiny\sin(x + y) = \sin x \cos y + \cos x \sin y.
  • sin(xy)=sinxcosycosxsiny\sin(x - y) = \sin x \cos y - \cos x \sin y.
  • tan(x+y)=tanx+tany1tanxtany\tan(x + y) = \frac{\tan x + \tan y}{1 - \tan x \tan y}.
  • tan(xy)=tanxtany1+tanxtany\tan(x - y) = \frac{\tan x - \tan y}{1 + \tan x \tan y}.
  • cot(x+y)=cotxcoty1coty+cotx\cot(x + y) = \frac{\cot x \cot y - 1}{\cot y + \cot x}.
  • cot(xy)=cotxcoty+1cotycotx\cot(x - y) = \frac{\cot x \cot y + 1}{\cot y - \cot x}.
  • cos(π2x)=sinx\cos(\frac{\pi}{2} - x) = \sin x and sin(π2x)=cosx\sin(\frac{\pi}{2} - x) = \cos x.
  • cos(π±x)=cosx\cos(\pi \pm x) = -\cos x, sin(πx)=sinx\sin(\pi - x) = \sin x, sin(π+x)=sinx\sin(\pi + x) = -\sin x.

Multiple Angles (Double and Triple Angles):

  • cos2x=cos2xsin2x=2cos2x1=12sin2x=1tan2x1+tan2x\cos 2x = \cos^2 x - \sin^2 x = 2\cos^2 x - 1 = 1 - 2\sin^2 x = \frac{1 - \tan^2 x}{1 + \tan^2 x}. → [JEE TIP] The rearrangements 1+cos2x=2cos2x1 + \cos 2x = 2\cos^2 x and 1cos2x=2sin2x1 - \cos 2x = 2\sin^2 x are arguably the most frequently used substitutions in JEE Calculus (Integration/Limits).
  • sin2x=2sinxcosx=2tanx1+tan2x\sin 2x = 2\sin x \cos x = \frac{2\tan x}{1 + \tan^2 x}.
  • tan2x=2tanx1tan2x\tan 2x = \frac{2\tan x}{1 - \tan^2 x}.
  • sin3x=3sinx4sin3x\sin 3x = 3\sin x - 4\sin^3 x.
  • cos3x=4cos3x3cosx\cos 3x = 4\cos^3 x - 3\cos x.
  • tan3x=3tanxtan3x13tan2x\tan 3x = \frac{3\tan x - \tan^3 x}{1 - 3\tan^2 x}.

Sum to Product (Factorization) Formulae:

  • cosx+cosy=2cosx+y2cosxy2\cos x + \cos y = 2\cos\frac{x+y}{2} \cos\frac{x-y}{2}.
  • cosxcosy=2sinx+y2sinxy2\cos x - \cos y = -2\sin\frac{x+y}{2} \sin\frac{x-y}{2}. → [JEE TIP] Pay attention to the negative sign here! It is a massive source of calculation errors. Alternatively, written as 2sinx+y2sinyx22\sin\frac{x+y}{2} \sin\frac{y-x}{2}.
  • sinx+siny=2sinx+y2cosxy2\sin x + \sin y = 2\sin\frac{x+y}{2} \cos\frac{x-y}{2}.
  • sinxsiny=2cosx+y2sinxy2\sin x - \sin y = 2\cos\frac{x+y}{2} \sin\frac{x-y}{2}.

Product to Sum (Defactorization) Formulae:

  • 2cosxcosy=cos(x+y)+cos(xy)2\cos x \cos y = \cos(x+y) + \cos(x-y).
  • 2sinxsiny=cos(x+y)cos(xy)-2\sin x \sin y = \cos(x+y) - \cos(x-y).
  • 2sinxcosy=sin(x+y)+sin(xy)2\sin x \cos y = \sin(x+y) + \sin(x-y).
  • 2cosxsiny=sin(x+y)sin(xy)2\cos x \sin y = \sin(x+y) - \sin(x-y).

Standard Derived Values:

  • sin15=3122\sin 15^\circ = \frac{\sqrt{3} - 1}{2\sqrt{2}}.
  • tan15=23\tan 15^\circ = 2 - \sqrt{3}.
  • tan22.5=21\tan 22.5^\circ = \sqrt{2} - 1.

Conditions & Limitations

Formulas involving tangents, cotangents, secants, and cosecants have strict domain restrictions where denominators become zero:

  • tan(x+y)\tan(x + y) identity is ONLY valid if none of the angles xx, yy, and (x+y)(x + y) is an odd multiple of π2\frac{\pi}{2}. If (x+y)=π2(x+y) = \frac{\pi}{2}, the right side approaches infinity, meaning you should use cot(x+y)=0\cot(x+y) = 0 instead.
  • tan(xy)\tan(x - y) identity is ONLY valid if none of the angles xx, yy, and (xy)(x - y) is an odd multiple of π2\frac{\pi}{2}.
  • cot(x+y)\cot(x + y) and cot(xy)\cot(x - y) identities are ONLY valid if none of the angles xx, yy, (x+y)(x+y), or (xy)(x-y) is a multiple of π\pi.
  • The half-angle substitution sin2x=2tanx1+tan2x\sin 2x = \frac{2\tan x}{1 + \tan^2 x} and cos2x=1tan2x1+tan2x\cos 2x = \frac{1 - \tan^2 x}{1 + \tan^2 x} is valid provided x(2n+1)π2x \ne (2n+1)\frac{\pi}{2}.

JEE Advanced Topics

  • Maximum and Minimum Values: The expression f(x)=asinx+bcosx+cf(x) = a\sin x + b\cos x + c has a maximum value of c+a2+b2c + \sqrt{a^2+b^2} and a minimum value of ca2+b2c - \sqrt{a^2+b^2}.
    • → [JEE TIP] Always ensure the angle 'xx' is exactly the same for both sine and cosine before applying this rule.
  • Trigonometric Series (Angles in A.P.):
    • sinα+sin(α+β)+sin(α+2β)+...+sin(α+(n1)β)=sin(nβ2)sin(β2)sin(α+(n1)β2)\sin \alpha + \sin(\alpha+\beta) + \sin(\alpha+2\beta) + ... + \sin(\alpha+(n-1)\beta) = \frac{\sin(\frac{n\beta}{2})}{\sin(\frac{\beta}{2})} \sin(\alpha + (n-1)\frac{\beta}{2})
    • cosα+cos(α+β)+cos(α+2β)+...+cos(α+(n1)β)=sin(nβ2)sin(β2)cos(α+(n1)β2)\cos \alpha + \cos(\alpha+\beta) + \cos(\alpha+2\beta) + ... + \cos(\alpha+(n-1)\beta) = \frac{\sin(\frac{n\beta}{2})}{\sin(\frac{\beta}{2})} \cos(\alpha + (n-1)\frac{\beta}{2})
  • Cosine Product Series:
    • cosAcos2Acos4A...cos(2n1A)=sin(2nA)2nsinA\cos A \cos 2A \cos 4A ... \cos(2^{n-1}A) = \frac{\sin(2^n A)}{2^n \sin A}.
  • Conditional Identities for Triangles (A + B + C = π):
    • sin2A+sin2B+sin2C=4sinAsinBsinC\sin 2A + \sin 2B + \sin 2C = 4\sin A \sin B \sin C
    • tanA+tanB+tanC=tanAtanBtanC\tan A + \tan B + \tan C = \tan A \tan B \tan C
    • cotAcotB+cotBcotC+cotCcotA=1\cot A \cot B + \cot B \cot C + \cot C \cot A = 1

⚠️ COMMON MISCONCEPTIONS & SIGN CONVENTIONS

  • Sign Traps with Square Roots: When solving cos2x=1625\cos^2 x = \frac{16}{25}, it implies cosx=±45\cos x = \pm \frac{4}{5}. Do not blindly assume the positive root. You must check which quadrant xx lies in to select the correct sign.
  • Half Angle Ambiguity: When finding sinx2\sin\frac{x}{2} given cosx=13\cos x = -\frac{1}{3} and xx in Quadrant III, you must narrow the interval. If π<x<3π2\pi < x < \frac{3\pi}{2}, then dividing by 2 gives π2<x2<3π4\frac{\pi}{2} < \frac{x}{2} < \frac{3\pi}{4}. Thus, x2\frac{x}{2} is in Quadrant II, meaning sinx2\sin\frac{x}{2} is positive, but cosx2\cos\frac{x}{2} is negative.
  • Reference Frame vs Angles: The symbols \infty and -\infty in tangent limits simply specify the type of asymptotic behavior, not actual numerical values. Tangent does not "equal" infinity; it increases arbitrarily.
  • sin(x+y)\sin(x+y) simplification: Never distribute trigonometric functions! sin(x+y)sinx+siny\sin(x+y) \ne \sin x + \sin y. It expands into a combination of sines and cosines.

Previous Year JEE Topics

  • Series evaluation: Evaluating large sums of trigonometric ratios (like telescoping series using tan(AB)\tan(A-B) or the A.P. series formulas).
  • Range of composite trigonometric functions: Utilizing the bounds of asinx+bcosxa\sin x + b\cos x combined with quadratic formulations (e.g., finding the range of sin4x+cos4x\sin^4 x + \cos^4 x).
  • Equation counting: Finding the number of solutions of sin()=cos()\sin(\dots) = \cos(\dots) in a given interval [0,2π][0, 2\pi] or [2π,2π][-2\pi, 2\pi] by plotting graphs and counting intersection points.
  • Half-angle tangent substitution: Rationalizing integrands in Calculus using t=tan(x/2)t = \tan(x/2).

Memory Aids & JEE Traps

  • → [JEE TIP] Trap 1 - "The π/4 Identity": Memorize tan(π4+x)=1+tanx1tanx\tan(\frac{\pi}{4} + x) = \frac{1+\tan x}{1-\tan x} and tan(π4x)=1tanx1+tanx\tan(\frac{\pi}{4} - x) = \frac{1-\tan x}{1+\tan x}. This appears repeatedly in coordinate geometry and integration.
  • → [JEE TIP] Trap 2 - "The Hidden Difference of Squares": sin(x+y)sin(xy)=sin2xsin2y=cos2ycos2x\sin(x+y)\sin(x-y) = \sin^2 x - \sin^2 y = \cos^2 y - \cos^2 x. Do NOT write this as sin2(xy)\sin^2(x-y).
  • → [JEE TIP] Trap 3 - "Degree to Radian oversight": In Calculus, the derivative formula ddx(sinx)=cosx\frac{d}{dx}(\sin x) = \cos x is ONLY true if xx is in radians. If xx is in degrees, ddx(sinx)=π180cosx\frac{d}{dx}(\sin x^\circ) = \frac{\pi}{180}\cos x^\circ.

Top 10 JEE MCQ Traps

  1. Misconception \rightarrow Assuming cos2x=cosx\sqrt{\cos^2 x} = \cos x universally. Correct Understanding \rightarrow cos2x=cosx\sqrt{\cos^2 x} = |\cos x|. It resolves to cosx-\cos x if xx is in the 2nd or 3rd quadrants.
  2. Misconception \rightarrow Thinking that since secx\sec x and cosec x\text{cosec } x are reciprocals of sine and cosine, their range is the reciprocal of [1,1][-1, 1] (i.e. just bounds). Correct Understanding \rightarrow The range strictly excludes the interval (1,1)(-1, 1). Values like secx=0.5\sec x = 0.5 have zero solutions.
  3. Misconception \rightarrow Using cosAcosB=2sin(A+B2)sin(AB2)\cos A - \cos B = 2\sin(\frac{A+B}{2})\sin(\frac{A-B}{2}). Correct Understanding \rightarrow Missing the negative sign! It is 2sin(A+B2)sin(AB2)-2\sin(\frac{A+B}{2})\sin(\frac{A-B}{2}) OR 2sin(A+B2)sin(BA2)2\sin(\frac{A+B}{2})\sin(\frac{B-A}{2}).
  4. Misconception \rightarrow Setting tan(A+B)\tan(A+B) formula equal to a value without checking the limits. Correct Understanding \rightarrow The formula tan(A+B)\tan(A+B) is undefined if A+B=90A+B = 90^\circ. If A+B=90A+B = 90^\circ, directly use cot(A+B)=0\cot(A+B) = 0 or 1tanAtanB=01 - \tan A \tan B = 0.
  5. Misconception \rightarrow The maximum value of sinxcosx\sin x \cos x is 1 because sinx\sin x max is 1 and cosx\cos x max is 1. Correct Understanding \rightarrow Variables are coupled. Multiply and divide by 2 to get 12sin2x\frac{1}{2}\sin 2x. The maximum value is 1/21/2.
  6. Misconception \rightarrow Assuming asinx+bcosya\sin x + b\cos y has a max of a2+b2\sqrt{a^2+b^2}. Correct Understanding \rightarrow The variables xx and yy are independent here. The maximum is simply a+b|a| + |b|. The a2+b2\sqrt{a^2+b^2} rule applies ONLY to asinx+bcosxa\sin x + b\cos x (same angle).
  7. Misconception \rightarrow sin1(sin(x))=x\sin^{-1}(\sin(x)) = x for all xx. Correct Understanding \rightarrow True only if x[π/2,π/2]x \in [-\pi/2, \pi/2]. Otherwise, you must fold xx back into the principal domain using reference angles (e.g. sin(2πx)\sin(2\pi - x)).
  8. Misconception \rightarrow In a triangle, if sinA=sinB\sin A = \sin B, then A=BA = B. Correct Understanding \rightarrow It could also be A=180BA = 180^\circ - B. Always account for the obtuse angle possibility unless other data constraints rule it out.
  9. Misconception \rightarrow Solving sinx=k\sin x = k by only writing the first quadrant principal angle x=sin1kx = \sin^{-1} k. Correct Understanding \rightarrow You lose infinite solutions. The correct general solution is x=nπ+(1)nsin1kx = n\pi + (-1)^n \sin^{-1} k.
  10. Misconception \rightarrow Canceling cosx\cos x from both sides of the equation sinxcosx=cosx\sin x \cos x = \cos x to get sinx=1\sin x = 1. Correct Understanding \rightarrow Never divide by a variable expression without accounting for it being zero. Doing so loses the solutions where cosx=0\cos x = 0 (x=π/2,3π/2x = \pi/2, 3\pi/2). Factor instead: cosx(sinx1)=0\cos x (\sin x - 1) = 0.
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