Math · Calculus

Continuity and Differentiability revision notes for JEE

A concise revision note for Continuity and Differentiability — the whole chapter on one page.

Revision note30 formulas alongside

01Key Concepts & Definitions

Continuity (Informal)
A function is continuous at a fixed point if its graph can be drawn around that point without lifting the pen from the plane of the paper.
Continuity at a Point
A function ff is continuous at x=cx = c in its domain if the limit of the function at x=cx = c equals the value of the function at x=cx = c.
  • Formula: lim⁡x→c−f(x)=lim⁡x→c+f(x)=f(c)\lim_{x \to c^-} f(x) = \lim_{x \to c^+} f(x) = f(c).
Continuity in an Interval
A function is continuous if it is continuous at every point in its domain. For a closed interval [a,b][a, b], ff must be right-continuous at x=ax = a (lim⁡x→a+f(x)=f(a)\lim_{x \to a^+} f(x) = f(a)) and left-continuous at x=bx = b (lim⁡x→b−f(x)=f(b)\lim_{x \to b^-} f(x) = f(b)),.
Infinity as a Limit
If a limit shoots up to +∞+\infty or drops to −∞-\infty, the limit does not exist as a real number, because ±∞\pm\infty are NOT real numbers,.
Differentiability at a Point
A function ff is differentiable at cc if the left-hand derivative (LHD) and right-hand derivative (RHD) are finite and equal.
  • First Principle of Derivative: f′(c)=lim⁡h→0f(c+h)−f(c)hf'(c) = \lim_{h \to 0} \frac{f(c+h) - f(c)}{h}.
  • LHD: lim⁡h→0−f(c+h)−f(c)h\lim_{h \to 0^-} \frac{f(c+h) - f(c)}{h} and RHD: lim⁡h→0+f(c+h)−f(c)h\lim_{h \to 0^+} \frac{f(c+h) - f(c)}{h}.
Explicit vs Implicit Functions
If a relationship between xx and yy can be easily solved to write y=f(x)y = f(x), yy is an explicit function. If it cannot be easily isolated, yy is given implicitly,.
Parameter
When the relation between two variables xx and yy is established via a third variable tt, tt is called the parameter, yielding parametric equations x=f(t),y=g(t)x = f(t), y = g(t),.

02Continuity of Standard Functions

  • Polynomial & Constant Functions: Always continuous everywhere in R\mathbb{R},,.
  • Identity Function (f(x)=xf(x) = x): Continuous at every real number.
  • Rational Functions (f(x)=p(x)/q(x)f(x) = p(x)/q(x)): Continuous everywhere in their domain (i.e., at all points where q(x)≠0q(x) \neq 0).
  • Trigonometric Functions: Sine and Cosine are continuous everywhere. Tangent, cotangent, secant, and cosecant are continuous everywhere in their respective domains,,.
  • Modulus Function (∣x∣|x|): Continuous at all real numbers, including at x=0x = 0 where the graph turns sharply,.
  • Greatest Integer Function ([x][x]): Discontinuous at every integral point. The limit approaching an integer cc from the left is c−1c-1, and from the right is cc,. JEE Tip Whenever a piecewise function or GIF is present, check continuity and limits exactly at the integral points or interval boundaries, as these are primary MCQ traps.

03Algebra of Continuous & Composite Functions

If ff and gg are continuous at x=cx = c:

  1. f+gf + g and f−gf - g are continuous at x=cx = c.
  2. f⋅gf \cdot g is continuous at x=cx = c.
  3. f/gf / g is continuous at x=cx = c (provided g(c)≠0g(c) \neq 0).
  4. λf\lambda f is continuous for any real constant λ\lambda.
  • Composite Functions: If gg is continuous at cc and ff is continuous at g(c)g(c), then the composite function (f∘g)(x)=f(g(x))(f \circ g)(x) = f(g(x)) is continuous at cc. JEE Tip In JEE questions involving f(∣x∣)f(|x|) or ∣f(x)∣|f(x)|, use composite function theorems. Since ∣x∣|x| is continuous, if f(x)f(x) is continuous, then f(∣x∣)f(|x|) and ∣f(x)∣|f(x)| are guaranteed continuous.

04Differentiability and its Relation to Continuity

  • Theorem: Every differentiable function is continuous.
  • Converse: Every continuous function is NOT necessarily differentiable. (e.g., f(x)=∣x∣f(x) = |x| is continuous at x=0x=0 but not differentiable there, as LHD = −1-1 and RHD = 11). JEE Tip Sharp corners or cusps on a continuous graph always indicate points of non-differentiability.

05Exponential and Logarithmic Functions

  • Exponential Function (f(x)=bxf(x) = b^x, where b>1b > 1): Domain is R\mathbb{R}, Range is R+\mathbb{R}^+. The point (0,1)(0, 1) is always on the graph. The graph is strictly increasing and asymptotic to the negative x-axis,.
  • Natural Exponential Function (f(x)=exf(x) = e^x): Base is ee (a number between 2 and 3 derived from the series 1+1/1!+1/2!+...1 + 1/1! + 1/2! + ...).
Logarithmic Function (log⁡bx\log_b x)

The inverse of the exponential function. If by=xb^y = x, then log⁡bx=y\log_b x = y.

  • Domain: Positive real numbers (R+\mathbb{R}^+).
  • Range: All real numbers (R\mathbb{R}).
  • The point (1,0)(1, 0) is always on the graph.
  • The graphs of exe^x and ln⁡x\ln x are mirror images across the line y=xy = x.
Properties of Logarithms

  1. Base Change: log⁡ap=log⁡bplog⁡ba\log_a p = \frac{\log_b p}{\log_b a}.
  2. Product Rule: log⁡b(pq)=log⁡bp+log⁡bq\log_b (pq) = \log_b p + \log_b q.
  3. Quotient Rule: log⁡b(p/q)=log⁡bp−log⁡bq\log_b (p/q) = \log_b p - \log_b q.
  4. Power Rule: log⁡b(pn)=nlog⁡bp\log_b (p^n) = n \log_b p.
  5. Exponential Identity: x=elog⁡xx = e^{\log x} is valid ONLY for x>0x > 0. JEE Tip Always verify x>0x>0 before applying logarithmic transformations. Applying logs to negative numbers or zero is a lethal trap.

06Methods of Differentiation

  1. Chain Rule (Composite Functions): If f=v∘uf = v \circ u, t=u(x)t = u(x), and both dt/dxdt/dx and dv/dtdv/dt exist, then dfdx=dvdt⋅dtdx\frac{df}{dx} = \frac{dv}{dt} \cdot \frac{dt}{dx}. Can be extended to any number of nested functions (e.g., dfdx=dwds⋅dsdt⋅dtdx\frac{df}{dx} = \frac{dw}{ds} \cdot \frac{ds}{dt} \cdot \frac{dt}{dx}).
  2. Implicit Differentiation: Differentiate both sides of the equation with respect to xx, applying the chain rule to terms involving yy (yielding a dy/dxdy/dx factor), then group and solve algebraically for dy/dxdy/dx,.
  3. Logarithmic Differentiation: Used for functions of the form y=[u(x)]v(x)y = [u(x)]^{v(x)}.
    • Take the natural logarithm of both sides: log⁡y=v(x)log⁡[u(x)]\log y = v(x) \log[u(x)].
    • Differentiate implicitly: 1ydydx=v′(x)log⁡[u(x)]+v(x)u′(x)u(x)\frac{1}{y} \frac{dy}{dx} = v'(x) \log[u(x)] + v(x) \frac{u'(x)}{u(x)}.
    • Condition: Both f(x)f(x) and u(x)u(x) MUST be strictly positive for their logarithms to be defined.
  4. Parametric Differentiation: For x=f(t),y=g(t)x = f(t), y = g(t), the derivative is: dydx=dy/dtdx/dt=g′(t)f′(t)\frac{dy}{dx} = \frac{dy/dt}{dx/dt} = \frac{g'(t)}{f'(t)}, provided f′(t)≠0f'(t) \neq 0.
  5. Higher Order Derivatives: Second-order derivative is d2ydx2=ddx(dydx)\frac{d^2y}{dx^2} = \frac{d}{dx}(\frac{dy}{dx}), denoted as f′′(x),y′′,y2, or D2yf''(x), y'', y_2, \text{ or } D^2y.

07Mean Value Theorems & Advanced JEE Concepts

  • Rolle's Theorem: If f(x)f(x) is continuous on [a,b][a, b], differentiable on (a,b)(a, b), and f(a)=f(b)f(a) = f(b), then there exists at least one c∈(a,b)c \in (a, b) such that f′(c)=0f'(c) = 0.
  • Lagrange's Mean Value Theorem (LMVT): If f(x)f(x) is continuous on [a,b][a, b] and differentiable on (a,b)(a, b), there exists at least one c∈(a,b)c \in (a, b) such that f′(c)=f(b)−f(a)b−af'(c) = \frac{f(b) - f(a)}{b - a}. JEE Tip LMVT is heavily tested in inequality proofs and finding the number of roots of equations.
  • L'Hôpital's Rule: Used for 0/00/0 or ∞/∞\infty/\infty indeterminate forms. lim⁡x→af(x)g(x)=lim⁡x→af′(x)g′(x)\lim_{x \to a} \frac{f(x)}{g(x)} = \lim_{x \to a} \frac{f'(x)}{g'(x)}.
  • Differentiation of Inverse Functions: If g(x)g(x) is the inverse of f(x)f(x) (i.e., f(g(x))=xf(g(x)) = x), then g′(x)=1f′(g(x))g'(x) = \frac{1}{f'(g(x))}.
  • Differentiation of Determinants: To differentiate a determinant Δ(x)\Delta(x), differentiate row-by-row (or column-by-column), adding the resulting determinants together.

08Formulae, Equations & Units

Algebra of Limits/Derivatives:

  • Product Rule (Leibnitz): (uv)′=u′v+uv′(uv)' = u'v + uv'.
  • Quotient Rule: (uv)′=u′v−uv′v2(\frac{u}{v})' = \frac{u'v - uv'}{v^2} (where v≠0v \neq 0).

Standard Derivative Formulae:

Function f(x)f(x)Derivative f′(x)f'(x)Conditions / DomainSource
xnx^nnxn−1n x^{n-1}x∈Rx \in \mathbb{R} for integer n>0n>0
sin⁡x\sin xcos⁡x\cos xx∈Rx \in \mathbb{R}
cos⁡x\cos x−sin⁡x-\sin xx∈Rx \in \mathbb{R}
tan⁡x\tan xsec⁡2x\sec^2 xx≠(2n+1)π2x \neq (2n+1)\frac{\pi}{2}
exe^xexe^xx∈Rx \in \mathbb{R}
log⁡x\log x1/x1/xx>0x > 0
axa^xaxlog⁡aa^x \log aa>0a > 0
sin⁡−1x\sin^{-1} x11−x2\frac{1}{\sqrt{1-x^2}}x∈(−1,1)x \in (-1, 1),
cos⁡−1x\cos^{-1} x−11−x2\frac{-1}{\sqrt{1-x^2}}x∈(−1,1)x \in (-1, 1)
tan⁡−1x\tan^{-1} x11+x2\frac{1}{1+x^2}x∈Rx \in \mathbb{R}

09Conditions & Limitations

  • Quotient Rule / Rational Functions: Functions of the form p(x)/q(x)p(x)/q(x) are strictly undefined, and their derivatives are invalid, wherever the denominator q(x)=0q(x) = 0,.
  • Logarithmic Differentiation Constraints: When transforming y=[u(x)]v(x)y = [u(x)]^{v(x)} into log⁡y=v(x)log⁡u(x)\log y = v(x)\log u(x), u(x)u(x) MUST strictly be >0>0. If the base can be negative, standard logarithmic differentiation fails.
  • Inverse Trigonometric Derivatives: The derivative of sin⁡−1x\sin^{-1}x is 11−x2\frac{1}{\sqrt{1-x^2}}. This is undefined at x=±1x = \pm 1 because the tangent to the inverse sine curve becomes perfectly vertical at the boundaries.

10Important Graphs & Diagrams

  • f(x)=1/xf(x) = 1/x: Approaches +∞+\infty as x→0+x \to 0^+, approaches −∞-\infty as x→0−x \to 0^-. Graph consists of two disjoint hyperbolas in Q1 and Q3,,.
  • Greatest Integer Function f(x)=[x]f(x) = [x]: A "step" graph. Flat on intervals [n,n+1)[n, n+1), jumping up at every integer. Discontinuous and non-differentiable at every integer,.
  • Exponential and Logarithmic Graphs: y=exy = e^x passes through (0,1)(0,1) and stays strictly in Q1 and Q2. y=ln⁡xy = \ln x passes through (1,0)(1,0) and stays strictly in Q1 and Q4. They are symmetrical mirror images of each other reflected across the line y=xy = x,,.
  • Polynomial Growth Comparison: Higher degree polynomials lean closer to the y-axis (grow faster). However, an exponential function (like 10x10^x or exe^x) will eventually grow faster and overtake ANY polynomial function xnx^n for large enough xx,,.

11COMMON MISCONCEPTIONS & SIGN CONVENTIONS

  • Infinity Trap: Assuming +∞+\infty or −∞-\infty is a valid limit value. Infinity is NOT a real number. If a limit evaluates to infinity, the limit does not exist. Similarly, continuity implies a finite limit,.
  • Drawing Without Lifting Pen Trap: Thinking that "drawing a graph without lifting a pen" is a perfectly rigorous definition of continuity. It is informal. The mathematical rigor strictly requires limit calculation,.
Parametric Double Derivative Error

A massive trap is assuming that d2ydx2=d2y/dt2d2x/dt2\frac{d^2y}{dx^2} = \frac{d^2y/dt^2}{d^2x/dt^2}. This is fundamentally false.

  • Correct rule: d2ydx2=ddt(dy/dtdx/dt)⋅dtdx\frac{d^2y}{dx^2} = \frac{d}{dt}\left(\frac{dy/dt}{dx/dt}\right) \cdot \frac{dt}{dx}.

12Previous Year JEE Topics

  1. Differentiability of ∣f(x)∣|f(x)|: Often tests identifying where a function inside a modulus changes sign.
  2. Functional Equations: e.g., f(x+y)=f(x)f(y)f(x+y) = f(x)f(y). Students must use the first principle limit definition to establish a differential equation (like f′(x)=k⋅f(x)f'(x) = k \cdot f(x)).
  3. Parametric higher-order differentiation: Extremely common in JEE Advanced coordinate geometry integrations.
  4. Implicit differentiation coupled with Inverse Trig: Using trigonometric substitutions (e.g., x=tan⁡θx = \tan \theta) to simplify inverse functions before differentiating,.

13JEE Traps

Continuity Does Not Imply Differentiability
✕Misconception

Differentiability implies continuity, so continuity implies differentiability.

✓Reality

Continuity is a necessary but not sufficient condition for differentiability. Check sharp corners (∣x∣|x| at 00 where LHD ≠\neq RHD).

Differentiating Variable Exponents
✕Misconception

For y=xxy = x^x, the derivative is x⋅xx−1x \cdot x^{x-1} (power rule) or xxlog⁡xx^x \log x (exponential rule).

✓Reality

Both rules are invalid because neither the base nor the exponent is constant. You MUST use logarithmic differentiation or rewrite as y=exln⁡xy = e^{x \ln x}. Never apply polynomial/exponential rules to variable^variable. Always take logs.

Parametric Second Derivative
✕Misconception

d2ydx2\frac{d^2y}{dx^2} of parametric equations x(t),y(t)x(t), y(t) is simply y′′(t)x′′(t)\frac{y''(t)}{x''(t)}.

✓Reality

d2ydx2=ddx(dydx)=ddt(y′(t)x′(t))×dtdx\frac{d^2y}{dx^2} = \frac{d}{dx}(\frac{dy}{dx}) = \frac{d}{dt}(\frac{y'(t)}{x'(t)}) \times \frac{dt}{dx}. Don't forget the dt/dxdt/dx chain rule factor at the end!

Domain of the Logarithm
✕Misconception

log⁡bx\log_b x domain is just x≠0x \neq 0.

✓Reality

The domain is strictly x>0x > 0. Negative logs are undefined in reals. Taking the log of an implicitly negative variable will wreck domain bounds.

Derivative of sin⁡−1(sin⁡x)\sin^{-1}(\sin x)
✕Misconception

y=sin⁡−1(sin⁡x)  ⟹  y′=1y = \sin^{-1}(\sin x) \implies y' = 1 always.

✓Reality

sin⁡−1(sin⁡x)=x\sin^{-1}(\sin x) = x ONLY in the principal domain [−π/2,π/2][-\pi/2, \pi/2]. Outside this, the graph is a zigzag line and the derivative alternates between 11 and −1-1 depending on the interval.

Infinite Limit Does Not Exist
✕Misconception

lim⁡x→01/x=∞\lim_{x\to 0} 1/x = \infty, so the limit exists.

✓Reality

∞\infty is not a real number. Also, RHL is +∞+\infty and LHL is −∞-\infty. The limit does not exist mathematically,.

Product of Continuous and Discontinuous
✕Misconception

f(x)g(x)f(x)g(x) is discontinuous if f(x)f(x) or g(x)g(x) is discontinuous.

✓Reality

If f(x)f(x) is continuous and g(x)g(x) is discontinuous at x=cx=c, their product CAN be continuous if f(c)=0f(c) = 0. E.g., x⋅sin⁡(1/x)x \cdot \sin(1/x) at x=0x=0.

x=eln⁡xx = e^{\ln x} Only for x>0x > 0
✕Misconception

x=eln⁡xx = e^{\ln x} applies for all real numbers.

✓Reality

It only holds true for x>0x > 0. For x≤0x \le 0, the right-hand side is undefined.

Derivative of x2\sqrt{x^2}
✕Misconception

Differentiating x2\sqrt{x^2} simply gives 11.

✓Reality

x2=∣x∣\sqrt{x^2} = |x|, so the derivative is +1+1 for x>0x>0 and −1-1 for x<0x<0. It is not differentiable at x=0x=0.

Sum of Non-Differentiable Functions
✕Misconception

The sum of two non-differentiable functions is always non-differentiable.

✓Reality

The sum can be perfectly differentiable. E.g., f(x)=∣x∣f(x) = |x| and g(x)=−∣x∣g(x) = -|x| are non-differentiable at 00, but their sum h(x)=0h(x) = 0 is differentiable everywhere.

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