Math · Coordinate Geometry and Vectors

Introduction to Three-dimensional Geometry revision notes

A concise JEE revision summary of Introduction to Three-dimensional Geometry.

FormulasRevision notes
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01Key Concepts & Definitions

1. The Rectangular Coordinate System In three-dimensional space, the position of a point is determined by three mutually perpendicular lines passing through a common point O. These lines are called the coordinate axes: the x-axis (X'OX), the y-axis (Y'OY), and the z-axis (Z'OZ). The point O is called the origin.

2. Coordinate Planes The three axes taken in pairs determine three mutually perpendicular planes called coordinate planes.

XY-plane
The plane containing the x and y axes.
YZ-plane
The plane containing the y and z axes.
ZX-plane
The plane containing the z and x axes.
JEE Tip
The perpendicular distance of any point P(x,y,z)P(x, y, z) from the YZ, ZX, and XY planes is given by x,y|x|, |y|, and z|z| respectively.

3. Octants and Sign Conventions The three coordinate planes divide the entire 3D space into eight distinct regions called octants (denoted as I, II, III, IV, V, VI, VII, VIII). The sign of the coordinates determines the specific octant in which a point lies.

Octant I (XOYZ)
(+, +, +)
Octant II (X'OYZ)
(-, +, +)
Octant III (X'OY'Z)
(-, -, +)
Octant IV (XOY'Z)
(+, -, +)
Octant V (XOYZ')
(+, +, -)
Octant VI (X'OYZ')
(-, +, -)
Octant VII (X'OY'Z')
(-, -, -)
Octant VIII (XOY'Z')
(+, -, -)

4. Direction Cosines (DC) & Direction Ratios (DR)

Direction Cosines (l,m,nl, m, n)
The cosines of the angles (α,β,γ\alpha, \beta, \gamma) made by a directed line with the positive directions of the x, y, and z-axes respectively.
Direction Ratios (a,b,ca, b, c)
Any three numbers that are proportional to the direction cosines of a line.
JEE Tip
Two parallel lines have the exact same direction cosines, but their direction ratios can be any proportional scalar multiples.

5. Historical Context The three coordinate planes used today were introduced by J. Bernoulli in 1715. Antoinne Parent gave a systematic development of analytical solid geometry in 1700, and L. Euler expanded on it systematically in 1748. Rene Descartes had the idea of 3D coordinates but did not develop it.

02Lines in 3D Space

1. Equation of a Line

Point-Parallel Form

The equation of a line passing through a point with position vector a\vec{a} and parallel to a vector b\vec{b} is r=a+λb\vec{r} = \vec{a} + \lambda\vec{b}.

  • Cartesian: xx1a=yy1b=zz1c=λ\frac{x-x_1}{a} = \frac{y-y_1}{b} = \frac{z-z_1}{c} = \lambda
Two-Point Form

The equation of a line passing through two points a\vec{a} and b\vec{b} is r=a+λ(ba)\vec{r} = \vec{a} + \lambda(\vec{b} - \vec{a}).

  • Cartesian: xx1x2x1=yy1y2y1=zz1z2z1\frac{x-x_1}{x_2-x_1} = \frac{y-y_1}{y_2-y_1} = \frac{z-z_1}{z_2-z_1}

2. Angle Between Two Lines

If two lines have direction ratios (a1,b1,c1)(a_1, b_1, c_1) and (a2,b2,c2)(a_2, b_2, c_2), the angle θ\theta between them is given by cosθ=a1a2+b1b2+c1c2a12+b12+c12a22+b22+c22\cos\theta = \frac{|a_1a_2 + b_1b_2 + c_1c_2|}{\sqrt{a_1^2+b_1^2+c_1^2}\sqrt{a_2^2+b_2^2+c_2^2}}.

  • JEE Tip For perpendicular lines: a1a2+b1b2+c1c2=0a_1a_2 + b_1b_2 + c_1c_2 = 0. For parallel lines: a1a2=b1b2=c1c2\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2}.

3. Skew Lines & Shortest Distance

Skew lines are lines in space that are neither parallel nor intersecting. They lie in different planes.

  • The shortest distance between lines r=a1+λb1\vec{r} = \vec{a_1} + \lambda\vec{b_1} and r=a2+μb2\vec{r} = \vec{a_2} + \mu\vec{b_2} is the projection of (a2a1)(\vec{a_2} - \vec{a_1}) along the vector perpendicular to both lines (b1×b2)(\vec{b_1} \times \vec{b_2}).

03Planes in 3D Space

1. Equation of a Plane

  • Normal Form: rn^=d\vec{r} \cdot \hat{n} = d, where dd is the perpendicular distance from the origin and n^\hat{n} is the unit normal vector.
Point-Normal Form

A plane passing through point a\vec{a} and perpendicular to vector n\vec{n} is (ra)n=0(\vec{r} - \vec{a}) \cdot \vec{n} = 0.

  • Cartesian: a(xx1)+b(yy1)+c(zz1)=0a(x-x_1) + b(y-y_1) + c(z-z_1) = 0
  • Intercept Form: xa+yb+zc=1\frac{x}{a} + \frac{y}{b} + \frac{z}{c} = 1, where a,b,ca, b, c are the x, y, and z intercepts respectively.

2. Family of Planes

The equation of a plane passing through the line of intersection of two planes P1=0P_1 = 0 and P2=0P_2 = 0 is P1+λP2=0P_1 + \lambda P_2 = 0.

  • JEE Tip Always evaluate the scalar λ\lambda by using the additional geometric condition given in the problem (like passing through a specific point or being perpendicular to another plane).

3. Distance and Image of a Point

  • The perpendicular distance of a point (x1,y1,z1)(x_1, y_1, z_1) from a plane Ax+By+Cz+D=0Ax + By + Cz + D = 0 is Ax1+By1+Cz1+DA2+B2+C2\frac{|Ax_1 + By_1 + Cz_1 + D|}{\sqrt{A^2 + B^2 + C^2}}.
  • JEE Tip The coordinates of the foot of the perpendicular (x,y,z)(x, y, z) from (x1,y1,z1)(x_1, y_1, z_1) to the plane is given by the symmetric ratio: xx1A=yy1B=zz1C=Ax1+By1+Cz1+DA2+B2+C2\frac{x-x_1}{A} = \frac{y-y_1}{B} = \frac{z-z_1}{C} = -\frac{Ax_1 + By_1 + Cz_1 + D}{A^2 + B^2 + C^2}. (To find the image, multiply the right-hand side by 2).

04Formulae, Equations & Units

1. Distance Formula The distance PQPQ between two points P(x1,y1,z1)P(x_1, y_1, z_1) and Q(x2,y2,z2)Q(x_2, y_2, z_2) is PQ=(x2x1)2+(y2y1)2+(z2z1)2PQ = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2}.

  • Distance from origin O(0,0,0)O(0,0,0) to point Q(x,y,z)Q(x,y,z) is OQ=x2+y2+z2OQ = \sqrt{x^2 + y^2 + z^2}.

2. Section Formula The coordinates of the point RR which divides the line segment joining points P(x1,y1,z1)P(x_1, y_1, z_1) and Q(x2,y2,z2)Q(x_2, y_2, z_2) in the ratio m:nm:n are:

  • Internal Division: (mx2+nx1m+n,my2+ny1m+n,mz2+nz1m+n)\left( \frac{mx_2 + nx_1}{m + n}, \frac{my_2 + ny_1}{m + n}, \frac{mz_2 + nz_1}{m + n} \right)
  • External Division: (mx2nx1mn,my2ny1mn,mz2nz1mn)\left( \frac{mx_2 - nx_1}{m - n}, \frac{my_2 - ny_1}{m - n}, \frac{mz_2 - nz_1}{m - n} \right)

3. Centroid of a Triangle and Tetrahedron

  • Triangle: For vertices (x1,y1,z1)(x_1, y_1, z_1), (x2,y2,z2)(x_2, y_2, z_2), and (x3,y3,z3)(x_3, y_3, z_3), the centroid GG is (x1+x2+x33,y1+y2+y33,z1+z2+z33)(\frac{x_1+x_2+x_3}{3}, \frac{y_1+y_2+y_3}{3}, \frac{z_1+z_2+z_3}{3}).
  • Tetrahedron: For four vertices, the centroid is (xi4,yi4,zi4)(\frac{\sum x_i}{4}, \frac{\sum y_i}{4}, \frac{\sum z_i}{4}).

4. Direction Cosine Identity For any line with direction cosines l,m,nl, m, n: l2+m2+n2=1l^2 + m^2 + n^2 = 1 (or cos2α+cos2β+cos2γ=1\cos^2\alpha + \cos^2\beta + \cos^2\gamma = 1).

  • JEE Tip Note that sin2α+sin2β+sin2γ=2\sin^2\alpha + \sin^2\beta + \sin^2\gamma = 2.

5. Shortest Distance Formula SD=(a2a1)(b1×b2)b1×b2SD = \frac{|(\vec{a_2} - \vec{a_1}) \cdot (\vec{b_1} \times \vec{b_2})|}{|\vec{b_1} \times \vec{b_2}|}

Variables: All spatial coordinates (x,y,zx, y, z) and distances are in generalized distance "units". Angles are in radians.

05Conditions & Limitations

  • Distance Formula Check: To prove collinearity using the distance formula, one must show that the sum of distances between two pairs of points equals the third distance (e.g., PQ+QR=PRPQ + QR = PR). Limitation: This method is computationally heavy. JEE Tip In JEE, it is much faster to prove collinearity by showing that the direction ratios of PQPQ and QRQR are proportional, or that the area of the triangle formed by them (via cross product) is zero.
  • Direction Ratios vs Cosines: The identity a2+b2+c2=1a^2 + b^2 + c^2 = 1 is strictly invalid for Direction Ratios unless they are explicitly normalized into Direction Cosines by dividing by a2+b2+c2\sqrt{a^2+b^2+c^2}.
  • Skew Lines Condition: The shortest distance formula for skew lines will yield 00 if the lines intersect. If the lines are parallel, the cross product b1×b2=0\vec{b_1} \times \vec{b_2} = 0, making the denominator zero. For parallel lines, use the specific parallel shortest distance formula: SD=(a2a1)×bbSD = \frac{|(\vec{a_2} - \vec{a_1}) \times \vec{b}|}{|\vec{b}|}.

06COMMON MISCONCEPTIONS & SIGN CONVENTIONS

Distance from Coordinate Axes vs Planes

A frequent error is confusing the distance of a point from an axis with its distance from a plane.

  • Distance of P(x,y,z)P(x,y,z) from the XY-plane is z|z|.
  • Distance of P(x,y,z)P(x,y,z) from the z-axis is x2+y2\sqrt{x^2 + y^2}. JEE Tip The coordinate (0,0,z)(0, 0, z) is the foot of the perpendicular from PP to the z-axis, making the distance formula yield x2+y2\sqrt{x^2 + y^2}.
  • Octant Sign Errors: Assuming that octants follow the 2D quadrant patterns exactly. While Octants I-IV mirror Quadrants I-IV with a positive zz, Octants V-VIII mirror them with a negative zz.
  • Image through Origin: The image of a point (x,y,z)(x, y, z) through the origin is (x,y,z)(-x, -y, -z). Its image through the X-axis is (x,y,z)(x, -y, -z) – the independent variable keeps its sign, while the others flip.
  • Right-Handed System: The vectors i^,j^,k^\hat{i}, \hat{j}, \hat{k} must strictly follow the right-hand thumb rule where i^×j^=k^\hat{i} \times \hat{j} = \hat{k}. If you arbitrarily assign axes without checking orthogonality and orientation, cross-product derivations will have inverted signs.

07Previous Year JEE Topics

Based on the historical frequency in JEE Main and Advanced, the following subtopics are heavily tested:

  1. Shortest distance between two skew lines (highest frequency).
  2. Image and foot of the perpendicular of a point on a plane or a line.
  3. Family of planes intersecting at a line, specifically finding a plane from the family that satisfies a distance condition.
  4. Locus of points satisfying a 3D distance relationship (e.g., PA2+PB2=2k2PA^2 + PB^2 = 2k^2).
  5. Coplanarity of lines (scalar triple product =0= 0).

08JEE Traps

JEE TipThe Plane Normal Trap

When finding the angle between a line and a plane, remember that the dot product formula bnbn\frac{\vec{b} \cdot \vec{n}}{|\vec{b}||\vec{n}|} yields sin(θ)\sin(\theta), NOT cos(θ)\cos(\theta). This is because n\vec{n} is the normal to the plane, so the angle between the line and the normal is 90θ90^\circ - \theta.

JEE TipThe Normalized Plane Equation

To find the perpendicular distance from the origin to a plane, the equation ax+by+cz=dax+by+cz=d MUST be normalized. The distance is da2+b2+c2\frac{d}{\sqrt{a^2+b^2+c^2}}, not just dd.

JEE TipSymmetrical Line Forms

When extracting direction ratios from a line equation, ensure the coefficients of x,y,zx, y, z are strictly +1+1. Example: If a line is 2x1=3y+2=z2x - 1 = 3y + 2 = z, you must rewrite it as x1/21/2=y+2/31/3=z1\frac{x - 1/2}{1/2} = \frac{y + 2/3}{1/3} = \frac{z}{1} before reading the direction ratios (1/2,1/3,1)(1/2, 1/3, 1).

The Axis Distance Illusion
Misconception

The shortest distance of a spatial point (x,y,z)(x,y,z) from the x-axis is simply its xx-coordinate.

Reality

The coordinate xx represents the perpendicular distance of the point from the YZ-plane. The true shortest distance of the point from the x-axis depends entirely on the remaining coordinates and is given by y2+z2\sqrt{y^2 + z^2}.

The Line-Plane Angle Trigonometric Switch
Misconception

The angle θ\theta between a straight line with direction vector b\vec{b} and a flat plane with normal vector n\vec{n} is computed using the standard cosine dot-product formula cosθ=bnbn\cos\theta = \frac{\vec{b} \cdot \vec{n}}{|\vec{b}||\vec{n}|}.

Reality

The standard dot product calculates the angle between the line and the normal vector of the plane. Because the true angle of interest is between the line and the surface of the plane, it is complementary (90θ90^\circ - \theta). Therefore, the calculation must strictly use sinθ=bnbn\sin\theta = \frac{\vec{b} \cdot \vec{n}}{|\vec{b}||\vec{n}|}.

Cosines vs. Ratios Identity Lock
Misconception

For any arbitrary triplet of numbers (a,b,c)(a, b, c) representing the directional components of a vector, the sum of their squares satisfies the identity a2+b2+c2=1a^2 + b^2 + c^2 = 1.

Reality

This mathematical identity holds strictly for Direction Cosines (l,m,nl, m, n), where l2+m2+n2=1l^2 + m^2 + n^2 = 1. Ordinary Direction Ratios (a,b,ca, b, c) are scalar multiples of cosines and do not satisfy this condition unless the vector is a unit vector.

The Collinearity Efficiency Bottleneck
Misconception

Utilizing the 3D distance formula to verify if AB+BC=ACAB + BC = AC is the most reliable and efficient way to check the collinearity of three points.

Reality

The distance formula involves nested square roots, which are highly time-consuming and prone to calculation errors under exam pressure. A much faster method is to check if the Direction Ratios of vector AB\vec{AB} and vector BC\vec{BC} are proportional, or to verify if their vector cross product is zero (AB×BC=0\vec{AB} \times \vec{BC} = \vec{0}).

Skew vs. Parallel Formula Blindness
Misconception

The standard shortest distance formula for skew lines ((a2a1)(b1×b2)b1×b2\frac{|(\vec{a_2}-\vec{a_1}) \cdot (\vec{b_1} \times \vec{b_2})|}{|\vec{b_1} \times \vec{b_2}|}) can be applied blindly to find the distance between any two non-intersecting lines in space.

Reality

If the two lines are parallel, their direction vectors are identical (b1=b2\vec{b_1} = \vec{b_2}), which makes the cross product b1×b2=0\vec{b_1} \times \vec{b_2} = \vec{0} and reduces the denominator to zero. You must always check if b1×b20\vec{b_1} \times \vec{b_2} \neq \vec{0} first. If they are parallel, switch to the parallel distance formula: (a2a1)×bb\frac{|(\vec{a_2}-\vec{a_1}) \times \vec{b}|}{|\vec{b}|}.

The Hidden Negative Direction Ratio
Misconception

In a symmetrical line equation written as 3x2=y+14\frac{3-x}{2} = \frac{y+1}{4}, the direction ratio corresponding to the xx-component is directly read as 22.

Reality

To correctly extract direction ratios, the line equation must strictly match the standard form where the variable coefficients are +1+1, i.e., (xx1)(x - x_1). Factoring out a negative from the numerator transforms the term into x32\frac{x-3}{-2}. Thus, the actual direction ratio for the xx-component is 2-2, not 22.

Diagrammatic Perpendicular Boundaries
Misconception

The coordinates of the foot of a perpendicular dropped from an external point (x1,y1,z1)(x_1, y_1, z_1) onto a plane must always fall inside the finite geometric boundaries sketched on rough paper.

Reality

Geometrically and algebraically, planes extend infinitely in all directions. The foot of the perpendicular is a mathematical projection that can easily lie far outside the arbitrary "triangle" or "parallelogram" boundaries drawn in a quick visualization sketch. Rely strictly on the algebraic formula.

The False Origin Intercept
Misconception

A plane equation presented in the form xa+yb+zc=0\frac{x}{a} + \frac{y}{b} + \frac{z}{c} = 0 is written in standard intercept form, with intercepts aa, bb, and cc.

Reality

The standard intercept form requires the Right-Hand Side (RHS) of the equation to be strictly equal to 11 (xa+yb+zc=1\frac{x}{a} + \frac{y}{b} + \frac{z}{c} = 1). If the RHS is 00, the plane passes directly through the coordinate origin (0,0,0)(0,0,0), making individual non-zero axis intercepts geometrically undefined.

The 2D vs. 3D Locus Dimension Shift
Misconception

The spatial locus of a point that maintains an equal distance from two fixed points in space is a straight line.

Reality

While this locus forms a straight perpendicular bisector line in a 2D plane, moving into 3D space adds an entire dimension of freedom. In three dimensions, the locus of a point equidistant from two fixed coordinates is an infinite perpendicular bisector plane.

The Scalar vs. Vector Projection Mix-Up
Misconception

The projection of a vector a\vec{a} onto another vector b\vec{b} is universally represented as a single scalar number.

Reality

JEE multiple-choice questions frequently exploit the distinction between two different terms. The scalar projection is indeed a magnitude (ab^\vec{a} \cdot \hat{b}), but the vector projection retains directional attributes and is expressed as a vector: (ab^)b^(\vec{a} \cdot \hat{b})\hat{b}. Always check the wording of the question carefully.

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